Hi guys, can someone with this assignment : for which value of p with the equation below have no real solutionpx^2 + 4x + 6 = 0i got so far, but stuck and not sure where to go further: px^2 + 4x + 6 = 0 > > i divide then everything with p x^2 + 4x/p + 6/p = 0 x= -4/2p +- √(-4/2p)^2 -6/px= -2/p +-√4/p -6/p i'm not sure where to go from here. can someone me. in advanced for any !

If there is no real solution the Discriminant (b^2 - 4ac) will have a value less than zero.  The a, b and c refer to the coefficients in the equation

ax^2 + bx + c = 0.

So for this equation  to have no real solution 4^2 - 4*p * 6 < 0

-24p + 16 < 0

-24p < -16

p > 16/24

p > 2/3

So the value of p must be greater than 2/3 for no real solutions,  (answer).

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