The angle of depression from the top of a cliff 50 metres above sea level to a ship sailing off the cliff is 22 degrees. how far is the yacht from the base of the cliff?

1) First step e

be x the distance of the ship till to cliff,  as you can observe the figure and applying   tangent in a triangle rectangle

tg α= CO / X⇒X = CO/tgα ⇒ X = 50/ tg 22° ⇒x = 123,75 the distance of the yacht  till the base of the cliff is 123,75 m

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

3

step-by-step explanation: