Use the student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (round your answer to three decimal places.)

The t critical value at 0.05 significance level for is:

Step-by-step explanation:

We are given confidence level =0.95

Significance level = 1 - confidence level

                              = 1 - 0.95

                               = 0. 05

Degrees of freedom = n - 1 = 17 - 1 = 16

Therefore, using the t distribution table, the t critical values are:

(3x-8) or (3x+8)

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".