Bonus question solve 2a-b+c= -5 a - b+c= -5 by subsittution 2a + b =5 a. a= -2,b=0,c = -2 b. a= -2,b=0,c = -1 c. a= 1,b = 3,c= -6 d. a= 1,b = 3,c = -4

Please find the answer below

Step-by-step explanation:

2a-b+c= -5 (A)

a-b+c= -5 (B)

2a+b =5 (C)

from equation A subtracting 2a from both sides we get

-b+c = -5-2a

Substituting this value in B

a-5-2a=-5

a-2a-5+5=0

-a=0

a=0

Putting this value in C

2(0)+b=5

b=5

Putting these values in B

0-5+c=-5

c=0

We do not have any option with these solutions . Hence, it seems that there is something missing from the equation.

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.