Atotal of 938 people attended the play. admission was $2.00 for adults and $0.75 for students. the total ticket sale amounted to $1,109. how many students and adults attended the play?

Let a represent the # of adults and s the # of students attending.

Since 938 people attended, a + s = 938, or s = 938 - a

Ticket sales to adults brought in $2.00(a) and ticket sales to students brought in $0.75s.  We must solve for a and s.

Let's do that via substitution of 938 - a for s:

$2.00a + $0.75(938-a) = $1109   (which was the total sales revenue)

Then 2.00a + 0.75(938) - 0.75a = 1109.  Combining like terms, we get:

1.25a = 1109 - 0.75(938), or  

1.25a = 1109 - 703.5, or:

1.25 a = 405.50

Dividing both sides by 1.25, we get:

a = 324.4

Let a represent the # of adults and s the # of students attending.

Since 938 people attended, a + s = 938, or s = 938 - a

Ticket sales to adults brought in $2.00(a) and ticket sales to students brought in $0.75s.  We must solve for a and s.

Let's eliminate s.  Solve a + s = 938 for a:  a = 938 - s.

Then $2(938 - s) + $0.75s = $1109.

This simplifies to $1876 - $2s + $0.75s = $1109, or

$1186 - $1109 = $1.25s.  Solving for s, we get s = 613.6

I did this problem twice, once by eliminating a and once by eliminating s.  Both times the number of students came out to be 613.6 and the number of adults 324.4.  This makes zero sense, since such a count MUST be integer.

Would you please double check to ensure that you've copied down this problem correctly.  Thank you.

d is the answer

step-by-step explanation:

total of apples - take away four

6-4 = 2

answer is 2 apples