How do i do this? method as well..

8x^3 + 12x^2 - 2x - 3.  This is the product in the form ax^3 + bx^2 + cx + d.

Step-by-step explanation:

We are told that the first and smallest of three consecutive positive integers is (2x - 1).  

The proper representation of the next integer is (2x - 1) + 2, or (2x + 1).

The third integer is (2x + 1) + 2, or (2x + 3).

The product of these three numbers is (2x - 1)(2x + 1)(2x + 3).

We need to multiply out this product.  Start with (2x - 1)(2x + 1).  This is a "special product" easily found:  (2x)^2 - 1, or 4x^2 - 1.

Now we have only to multiply this (4x^2 -1) by (2x + 3).  Using the FOIL method, we obtain:

8x^3 + 12x^2 - 2x - 3.  This is the product in the form ax^3 + bx^2 + cx + d.

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐