Write the function in vertex form y=x^2+6x+3

y = 1(x + 3)² - 6

Step-by-step explanation:

The standard form of a quadratic function is  

y = ax² + bx + c

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b/(2a) and k = f(h)

In the equation y= x² + 6x + 3

a = 1; b = 6; c = 3

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Calculate h

h = -6/(2×1)

h = -6/2

h = -3

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Calculate k

k = 1(-3)² + 6(-3) + 3

k = 9 - 18 +3

k = -6

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Write the vertex form of the equation

y = 1(x + 3)² - 6

The graph is a parabola with a vertex at (-3, -6).

step-by-step explanation:

i am not sure sorry : c