What is the area of a triangle with vertices at (−2, -3) , (6, -3) , and (2, 5) ?

Hello from MrBillDoesMath!

Answer :  32

Discussion:

Label the points as follows:

A  = (-2, -3),             B = ( 6, -3),    C = ( 2.5)

Area of a triangle = (1/2) bh

where "b" is the "base" and "h" is the height of the triangle.

In our case, the base is the line AB, so the length of the base is

    b = 6 - ( -2) =  6 + 2 = 8

(6 and -2 are the x coordinates of the points B and A, respectively)

The height is the distance from the y-coordinate of point C to the base AB. That is,

5 - (-3) = 5 + 3 = 8

(5 is the y coordinate of point C;  -3 is the y coordinate of the line AB)

Finally,

Area =   (1/2) * 8 * 8 = (1/2) 64 = 32

Thank you,

MrB

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.