When 328 college students are randomly selected and surveyed, it is found that 122 own a car. find a 99% confidence interval for the true proportion of all college students who own a car?

Step-by-step explanation:

We know that,

where

r = number of successful trials = 122,

n = 328

p = proportion

From probability distribution we also know that,

for a 99% confidence level = 2.576

Marginal error will be,

Putting the values,

So the interval will be,

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