Is it possible to solve a quadratic equation that is not factorable over the set of integers? explain.

YES, it is possible to solve a quadratic equation that is not factorable over the set of integers.

Step-by-step explanation:

A quadratic equation is a condition of the second degree, which means it contains no less than one term that is squared. The standard frame is

ax² + bx + c = 0

with a, b, and c being constants or numerical coefficients, and x is an obscure variable.

The quadratic equation includes just a single obscure, it is designated "univariate". Specifically, it is a second-degree polynomial condition, since the best power is two.

Whenever factorization fails you can use:

a) completing the square method  

b) quadratic formula

to solve the quadratic equation.

The answers can lead you to the complex numbers but there is always a solution.

1/5^2 = 7.56/45

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent