If p(x) = x2 – 1 and q(x) = 5(x-1) which expression is equivalent to (p – q)(x)? a) 5(x – 1) – x2 – 1 b) (5x – 1) – (x2 – 1) c) (x2 – 1) – 5(x – 1) d) (x2 – 1) – 5x – 1

Option C is correct.

The expression which is equivalent to (p-q)(x)  is,

Step-by-step explanation:

Given: and q(x) = 5(x-1)

To find the expression which is equivalent to (p-q)(x):

here p and q both are function assuming;

we can write the expression :

(p-q)(x) = p(x) - q(x) =

therefore, the expression which is equivalent to (p-q)(x)  is;  

idk sry

step-by-step explanation: