(a^4(3a^2b)^3)/((3ab^2)^-1) exponent has to be postive and has to be simplified

81a^8b^12

Step-by-step explanation:

When you have an exponent to an exponent multiply the exponents.

(3a^2b^3)^4

=81a^8b^12

Ed

To do this problem, you need to raise each of the individual terms inside the parentheses

to the 4th power.

In other words:

Now you can recognize that 3%5E4 is 3*3*3*3 and this product is 81. So you can substitute

81 in place of 3%5E4 and the problem is reduced to:

.

81%2A%28a%5E2%29%5E4%2A+%28b%5E3%29%5E4

.

Next look at %28a%5E2%29%5E4. You can get an equivalent form of this by multiplying the exponent

4 by the exponent 2 to get a%5E8. You can also think of %28a%5E2%29%5E4 as being a%5E2

mark branliest

step-by-step explanation:

.6 is 1/2 of 12

the answer is actually d. i just took the test

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3