The ratio of the length to the width of a picture is 5: 2. the picture is enlarged so that its length is 15 inches now. what is the width of the enlarged picture?

The picture's dimensions will be 10"x15".

Step-by-step explanation:

Length:   4      2     10

Width:     6      3     15

You can tell because 15 isn't divisible by 6, but it is divisible by 3, which goes into 6.

Divide 6 by 2.

6/2=3

To keep the ratio, we must also divide 4 by 2.

4/2=2

Then, multiply 3 by 5 for the width.

3*5=15

You must also multiply 2 by 5 to get the length.

2*5=10

The picture's dimensions will be 10"x15".

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: