What is the value of c in the function x^2-7x+c to make it a perfect square trinomial?

c = 49/4

Step-by-step explanation:

The given expression is x^2 - 7x + c

This trinomial must be a perfect square.

Therefore, c must be a prefect square number.

So b^2 - 4ac = 0. That is discriminant must be equal to zero.

In the given expression a =1 and b = -7

Now plug in these values in the discriminant formula.

(-7)^2 - 4*1*c = 0

49 -4c = 0

4c = 49

c =  49/4

x^2 - 7x + 49/4 = (x - 7/2)^2

which is perfect square trinomial.

Thank you.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.