how do you convert this to vertex form?

y = (x-3)^2

rewrite to make it match the form

y = 1*(x-3)^2 +0

Step-by-step explanation:

vertex form:  a(x-h)^2 +k

where (h,k) is the vertex

y= x^2 -6x+9

factor

y = (x-3)^2

rewrite to make it match the form

y = 1*(x-3)^2 +0

h=3

k=0

I don't know if they want they 1 and the zero included in your answer

step-by-step explanation:

your mom

a .4y4

hope this !