The dimensions of a square are altered so that 8 inches is added to one side while 3 inches is subtracted from the other. the area of the resulting rectangle is 126 in². what was the orriginal side length of the square?

Answer

Find out the original side length of the square .

To prove

Let us assume that the original length of the square be x.

Formula

As given

The dimensions of a square are altered so that 8 inches is added to one side while 3 inches is subtracted from the other.

Length becomes  = x + 8

Breadth becomes = x -3

The area of the resulting rectangle is 126 in²

Put in the formula

(x + 8) × (x - 3) = 126

x² -3x + 8x -24 = 126

x ²+ 5x = 126 +24

x² + 5x - 150 = 0

x² + 15x - 10x - 150 = 0

x (x + 15) -10 (x +15) =0

(x + 15)(x -10) =0

Thus

x = -15 , 10

As x = -15 (Neglected this value because the side of the square cannot be negative.)

Therefore x = 10 inches be the original side of the square.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^