Write an equation in point-slope form of the line that passes through the point (3,−8) and has a slope of 7

Point-slope form:

y - y₁ = m(x - x₁)                "m" is the slope

(x₁ , y₁) = (3, -8)

m = 7

Plug this into the equation

y - y₁ = m(x - x₁)  

y - (-8) = 7(x - 3)

y + 8 = 7(x - 3)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: