How do i solve this problem?

theta = all real values

Step-by-step explanation:

sec theta + tan theta  = cos theta / (1-sin theta )

sec theta = 1/cos theta

tan theta = sin theta/cos theta

1/cos theta + sin theta /cos theta= cos theta/ (1-sin theta)

(1+ sin theta) / cos theta = cos theta /( 1-sin theta)

using cross products

(1+sin theta) * (1-sin theta) = cos theta * cos theta

1 +sin theta - sin theta- sin^2 theta= cos ^2 theta

1 - sin ^2 theta= cos ^2 theta

cos ^2  theta= cos ^2 theta

this is an identity so it is true for all theta

step-by-step explanation:

abc

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).