Write an equation for a line that is parallel to the given line that passes through the given point. explain how you found the equation. y=2x+7; (3,11) show all work plz

Slope-intercept form:

y = mx + b   "m" is the slope, "b" is the y-intercept (the y value when x = 0)

For lines to be parallel, they have to have the SAME slope.

The given line's slope is 2, so the parallel line's slope is also 2.

y = 2x + b

To find "b", plug in the point (3,11) into the equation.

y = 2x + b

11 = 2(3) + b      Multiply 2 and 3

11 = 6 + b      Subtract 6 on both sides

5 = b

y = 2x + 5

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^