Median am and cn of △abc intersect at point o. what part of area of △abc is the area of △aon?

The area of △AON is th part of the area of △ABC.

Step-by-step explanation:

It is given that AM and CN are medians. The intersection point of medians is centroid. Median divides the triangle is two equal parts.

The centroid divides each median in a ratio of 2:1.

Therefore CO:ON is 2:1.

Let the area of △ABC be x.

Since CN is median therefore the area of triangle ANC and BNC are same and half of the total area of the triangle ABC.

Area of triangle ANC is .

The point O divide the median CN is 2:1. So the line AO divides the area in 2:1.

Area of triangle AON is rd of area of ANC. Area of AON is

The area of ABC is x and the area of AON is .

Therefore the area of △AON is th part of the area of △ABC.

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol