Solve by substitution x-2y= -25 and 3x-y=0

x=5 and y=15

Step-by-step explanation:

x−2y=−25

x−2y+2y=−25+2y(Add 2y to both sides)

x=2y−25

Step: Substitute2y−25forxin3x−y=0:

3x−y=0

3(2y−25)−y=0

5y−75=0(Simplify both sides of the equation)

5y−75+75=0+75(Add 75 to both sides)

5y=75

5y

5

=

75

5

(Divide both sides by 5)

y=15

Step: Substitute 15fory in x=2y−25:

x=2y−25

x=(2)(15)−25

x=5(Simplify both sides of the equation)

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.