If r(x) = 3x - 1 and s(x) = 2x + 1, which expression is equivalent

Value of the  \frac{r}{s} (6) =\frac{17}{13}  

Step-by-step explanation:

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)

we have two functions :

r(x) = 3x-1

s(x) = 2x+1

Find the value of  \frac{r}{s} (6)  

\frac{r}{s}(x) =\frac{r(x)}{s(x)}    

Firstly, we will find the value of r(6) and s(6).

In order to find the value of r(x) & s(x), we will put x = 6 in the given function r(x) & s(x).

r(6) = 3(6) - 1

r(6) = 18 - 1

r(6) = 17

and  

s(6) = 2(6) + 1

s(6) = 12 + 1

s(6) = 13

\frac{r}{s} =\frac{17}{13}  

hope this helped!

step-by-step :