Which points are on the graph of f(x)=(13) x? select each correct answer. a (3, 27) b (−2, 9) c (0, 1) d (−1, −13)]

B and C

Step-by-step explanation:

We are given that a function

A.(3,27)

Substitute x=3

Hence, it  is not true.

B.(-2,9)

Substitute x=-2

By using identity

Therefore, point(-2,9) lies on the given graph.

Hence, it is true.

C.(0,1)

Substitute x=0

By using

Hence, it is true.

D.(-1,-13)

Substitute x=-1

Hence, the point (-1,-13) does not lie on the graph.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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