What is the area of a triangle whose vertices are d(3, 3) , e(3, −1) , and f(−2, −5) what is the area of the rectangle?

The area of the triangle with the given vertices is 10 square units

Step-by-step explanation:

      x   y

D    3   3

E    3   -1

F   -2   -5

D    3   3

Area: A=Abs [(xd ye + xe yf + xf yd) - (yd xe + ye xf + yf xd)] /2

Absolute value: Abs

A = Abs { [(3)(-1)+(3)(-5)+(-2)(3)] - [(3)(3)+(-1)(-2)+(-5)(3)] } / 2

A = Abs [ (-3-15-6)-(9+2-15) ] / 2

A = Abs [ (-24)-(-4) ] / 2

A = Abs ( -24+4) / 2

A = Abs (-20) / 2

A = 20 / 2

A = 10 square units

the answer is b.)

< 1=< 2

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.