How much water should we add to 35 kg of sugar syrup to change its concentration from 30% to 25%?

7 kg of water.

Step-by-step explanation:

Given that the concentration of sugar in syrup is 30% of 35 kg, i.e. 10.5 kg.

Let's assume we add "X" quantity of water to reduce sugar concentration from 30% to 25%.

New quantity of sugar syrup would be (35 + X) kg, and sugar quantity is still 10.5 kg in the syrup. It says the new concentration is 25%.

Mathematically, sugar quantity = 25% of sugar syrup.

10.5 = 25% of (35 + X)

10.5 = 0.25 * (35 + X)

10.5 = 8.75 + 0.25X

10.5 - 8.75 = 0.25X

1.75 = 0.25X

X = 1.75 / 0.25 = 7

Hence, we should add 7 kg of water to to 35 kg of sugar syrup to change its concentration from 30% to 25%.

we will add 7 kg of water in 35 kg of sugar syrup to change e its concentration from 30% to 25%?

Step-by-step explanation:

we are Given

the concentration of sugar in syrup is 30% of 35 kg, i.e. 10.5 kg.

Let's imagine

we add "X" quantity of water to reduce sugar concentration from 30% to 25%.

New quantity of sugar syrup will be (35 + X) kg, and sugar quantity is still 10.5 kg in the syrup.

we can see that   new concentration is 25%.

now logically

sugar quantity = 25% of sugar syrup.

10.5 = 25% of (35 + X)

10.5 = 0.25 × (35 + X)

10.5 = 8.75 + 0.25X

10.5 - 8.75 = 0.25X

0.25X=1.75

x==7

x=7 kg of water

Hence, proved that we will add 7 kg of water to to 35 kg of sugar syrup to change its concentration from 30% to 25%.

answer is 67%

step-by-step explanation:

10 b/c 5*2 =10

step-by-step explanation: