The length of a new rectangular playing field is 9 yards longer than double the width. if the perimeter of the rectangular playing field is 336 yards, what are the dimensions

You can use the given description to form a symbolic expression for length and width. The given parameter will then help you to get the value of unknown measures.

The dimensions of the given rectangle are

Length = 112 yards

Width = 56 yards

Since we are given length in terms of its width, thus, lets suppose that

width = yards.

Then, we have:

Length = double of width = yards

The perimeter of a rectangle =   (given)

(remember that many times, when using letters or symbols, we hide multiplication and write two things which are multiplied, close to each other. As in )

Using above values for length and width in perimeter, we get

Thus, length is double of width = 2 times 56 = 112 yards.

Thus,

The dimensions of the given rectangle are

Length = 112 yards

Width = 56 yards

Learn more about rectangles here:

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Dimension of rectangular playing filed is 53 yards by 115 yards

Step-by-step explanation:

The length of rectangular playing filed is 9 yards more than double the width.

Let us suppose width of rectangular field = x yard

Width (w)= x yards

Length (l)= 2x+9

Perimeter of Rectangular field = 2(l+w)

We are given perimeter of rectangular playing filed = 336 yards

2(2x+9+x)=336

Now we solve for x

3x+9=168

3x=159

x=53 yards

Width = 53 yards

Length = 2(53)+9 = 115 yards  

Thus, Dimension of rectangular playing filed is 53 yard by 115 yards

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5