What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2

D=1

Step-by-step explanation:

d=1

Step-by-step explanation:

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

Now make the denominators same

LCD: (d-4)(d+2)

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1

5y

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°