If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (fxg)(x)?

The quick answer I think will help you in the long run is that (f*g)(x) is just another way of saying f(x)*g(x). If that is enough, then ignore the rest of my response. Otherwise, keep reading.

For this problem

Step-by-step explanation:(f*g)(x) = f(x)*g(x)

You are given f(x) = 3x + 2 and g(x) = x^2 + 1. Simply substitute these expressions as follows:

  f(x)*g(x) = (3x + 2)*(x^2 + 1)

Notice how I put each expression in parentheses. This practice will help immensely when dealing with more complicated expressions like this. Next, we simplify:

  (3x + 2)*(x^2 + 1) = (3x)(x^2) + (3x)(1) + (2)(x^2) + (2)(1) <-- the foil method

                               =     3x^3    +     3x    +   2x^2    +    2     <-- simplify each term

                               = 3x^3 + 2x^2 + 3x + 2                           <-- reorganize and group like terms

hope this helped!

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92