What is an equation of the line that is perpendicular to y-3=4(x+2) and passes through the point (-5,7)

The perpendicular line would be y = -1/4x + 23/4

Step-by-step explanation:

In order to find the equation of this line, we first have to note that perpendicular lines have opposite and reciprocal slopes. Therefore, since the original line has a slope of 4, we know the new line will have a slope of -1/4. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 7 = -1/4(x + 5)

y - 7 = -1/4x - 5/4

y = -1/4x + 23/4

i think is g(1)=-1.

hope that i can