Let f(x)= sqrt 6x and g(x)=x+3 smallest number that is in the domain of

***The complete question is: Let f(x)= sqrt 6x and g(x)=x+3 smallest number that is in the domain of f(g(x))***

The smallest number that is in the domain is -3.

Explanation:

Given functions:

To find f(g(x)), put g(x) in f(x) as follows:

As (6x+18) is in square-root (and square-root of a negative number is an imaginary value), therefore, the domain should be the following:

Therefore, the domain is [-3, +∞).

So the smallest number that is in the domain is -3.

ιт ιѕ вє¢αυѕє:

6: 4= 3/2

18: 8= 9/4

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