If g(x) = x^2 + 6x with x ≥ -3, find g ^-1(0). and explain how to get the answer if you can.

0

Step-by-step explanation:

g(x) = x² + 6x   ; x ≥ -3

To find the inverse, swap the x's and y's and solve for "y":

    x = y² + 6y

x + 9 = y² + 6y + 9   add 9 to both sides to create a perfect square

x + 9 = (y + 3)²

= y + 3   take square root of both sides

= y    ; y ≥ -3

g⁻¹(0) =

        =

        = -3 ± 3

        = -3 + 3   ,   -3 - 3

        =     0      ,      -6

since the restriction is: y ≥ -3, then -6 is not valid

if you need just tell me and i will come to the rescue.

step-by-step explanation: