The areas of the two watch faces have a ratio of 16: 25. what is the ratio of the radius of the smaller watch face to the radius of the larger watch face?

4:5

Step-by-step explanation:

Let r be the radius of small watch

Area of small watch=π

Let R be radius of larger watch= π

Area of larger watch= π

It is given that the ratio of their areas= 16:25

=

π: π= 16:25

=

r:R= 4:5

Hence, the ratio of their radii= 4:5

Hence, the correct answer is 4:5

true? is that what you're asking or do you mean something else?

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)