The stock market in 2008 has gone through drastic changes. on december 3rd, 2008 the dow jones industrial average (djia) closed the day at 8,591.69 points. on december 4th of the same year, the djia decreased by 2.51% of its december 3rd closing. on december 5th of the same year, the djia increased by 3.09% of its december 4th closing. determine what the djia closed at on december 5th. round your answer to the nearest point. a. 8,631.78 points c. 8,634.86 points b. 8,750.35 points d. 9,079.49 points

c. 8634.86 points

Step-by-step explanation:

A change of x% means the value is multiplied by 1+x% = 1+x/100. For a change of -2.51%, the value is multiplied by ...

... 1 - .0251 = 0.9749

For a change of +3.09%, the value is multiplied by ...

... 1 +.0309 = 1.0309

Then, for the two days, the value is multiplied by ...

... 0.9749 × 1.0309 = 1.00502441

So, at closing on December 5th, the DJIA was ...

... 8591.69 × 1.00502441 = 8634.86 . . . . points

Comment on answer choices

The problem statement tells you to "round your answer to the nearest point," but none of the answer choices are rounded that way. To the nearest point, the answer should be 8635 points.

Have your teacher tell you how the answer choices are consistent with the problem statement.

the answer is c

Step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: haha (: i’ll go see what it is

step-by-step explanation: