Evaluate the expression by using the given value of the variable. y ÷ 2 • 3 – 40 ÷ x + 2 where x = 5 and y = 6 question 4 options: –9 –5 11 3

The correct answer is 3

Step-by-step explanation:

To start, put the values in where you see the variables.

y ÷ 2 • 3 – 40 ÷ x + 2

6 ÷ 2 • 3 – 40 ÷ 5 + 2

Now complete all of the multiplication and division.

9 - 8 + 2

Now complete all the addition and subtraction.

3

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752