Wang yong owes the bank $8500$8500dollar sign, 8500. to repay the debt, he paid a fixed amount back to the bank each month. after 121212 months, his remaining debt was $6460$6460dollar sign, 6460.how much did wang yong pay each month? space$$dollar signhow long did it take wang yong to pay back his entire debt? space months

Given:

Wang Yong owes the bank $8500. He pays back a fixed amount each month. After 12 months, he still has to pay off $6460.

To Find:

The amount of money he pays the bank every month and how long it will take him to pay off the full debt.

Wang Yong pays $170 each month, and doing so, it will take him a total time of 50 months to pay off the full debt.

Step-by-step explanation:

Wang Yong has borrows $8500 according to the question.

Say he pays the bank an amount of x every month, which is fixed. After 12 months, he still has to pay $6460.

In 12 months, he would have paid the bank 12x.

But $6460 is still left out of the original $8500.

This means,

That is, Wang Yong pays the bank $170 every month.

Next, to calculate the amount of time it took Wang Yong to pay back his whole debt, we divide the total sum of money owed to the bank by the amount Wang Yong pays each month.

So, number of months = 8500 ÷ 170 = 50

That is, Wang Yong will pay off his debt 50 months after borrowing the money from the bank, provided he pays back $170 every month.

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.

its an acute right triangle

step-by-step explanation: