Plzz 40pts one day, gale and hector each recorded temperatures outside their homes. function g shows temperatures, in °f, gale recorded x hours after noon. the graph shows temperatures, in °f, hector recorded x hours after noon. select from the drop-down menus to complete the statement. at noon, the temperature outside of (gale; s, hector's) home degrees ,2 , 3 , 4 degrees) warmer than the temperature outside of 's, hector's) home.

 At noon the temperature outside of Hector's home was 4 degree warmer than the temperature outside of gale's home.  

Step-by-step explanation:

Here, x represents the number of hours after noon while g(x) and f(x) represents the temperature of gale's and hector's home respectively in x hours.

Since, at noon, x = 0

And, by the table g(x=0) = -1

That is, the temperature of gale's home is -1° F at noon.

And, by the given graph, f(x=0) = 3

That is, the the temperature of hector's home is 3° F at noon.

And,  f(0)-g(0) = 3-(-1) = 4°F

That is, the difference between  the temperature of hector's home at noon and the temperature of gale's home at noon is 4°F.

At noon the temperature outside of Hector's home was 4 degree warmer than the temperature outside of gale's home.

Step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

answer: answer is b.

[m < b = 120º]

step-by-step explanation: