The polynomial equation x3+x2=-9x-9 has complex roots +-3i . what is the other root? use a graphing calculator and a system of equations. –9 –1 0 1

x=-1

Step-by-step explanation:

x3+x2=-9x-9

add 9x +9 on each side

x^3+x^2+9x+9=-9x-9+9x+9

x^3+x^2+9x+9=0

factor out an x^2 from the left  2 terms and a 9 from  the right 2 terms

x^2 (x+1)  +9(x+1) = 0

factor out x+1

(x+1) (x^2+9) = 0

using the zero product property

x+1 =0    x^+9 =0

x=-1    x^2 =-9

x=-1     sqrt(x^2) = sqrt(-9)

x=-1     x = ±3i

fwms@lil_ben06

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.