(30 points) what are the y intercepts of the circle whose equation is (x+2)^2+(y-4)^2=13? a. 1 and 7 b. 4 plus or minus radical 17 c. there are no y intercepts !

Hello from MrBillDoesMath!

 Choice C

Discussion:

The y-intercepts are the x values where y = 0.   Substituting y = 0 in the equation gives

(x+2)^2 +  (0-4)^2 = 13 =>

(x+2)^2 + 16 = 13 =>

Subtract 16 from both sides

(x+2)^2 = 13 - 16 = -3     (*)

The square of a real number is greater than or equal to 0. (Not true for complex numbers). The left side of (*) is therefore >= 0 but as also equals -3. This is not possible so there is no solution to the equation. Choice C.

Thank you,

MrB

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

mark brainliest!

just sum

10 + 10 = 20