Ill give you ! plz im so desperate uwu

Hello from MrBillDoesMath!

 radius = 20

Discussion:

The distance between two complex points z1 ( = x1 + i y1) and z2 ( = x2 + iy2) is

sqrt ( (x1-x2)^2 + (y1-y2)^2)

In our case z1 =  -10 - 1i and z2 =  6 + 11i. Per the above formula, the distance, or radius of the circle, is given by

sqrt (  (-10 - 6)^2 +  ( -1 - 11)^2 )  =

sqrt ( ( -16)^2 + (-12)^2) )  =

sqrt ( 256 + 144) =

sqrt(400) =

20

Thank you,

MrB

The radius of the circle is maybe (-2, 5)

Step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

what is the information provided?

step-by-step explanation: