Round answer to the nearest tenth. an accident investigator measured the skid marks of one of the vehicles involved in an accident. the length of the skid marks was 175 feet. what was the speed of the vehicle before the brakes were applied?

The speed of the vehicle before the brake were applied was about 83.7 feet/s

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem!

This problem is about accelerated motion.

Given:

final speed of the vehicle = v = 0 feet/s

length of skid marks = d = 175 feet

maximum deceleration = a = 20 feet/s² ( assumption )

Unknown:

initial speed = u = ?

Solution:

(rounded to the nearest tenth)

The speed of the vehicle before the brake were applied was about 83.7 feet/s if we assume that maximum deceleration of the vehicle is about 20 feet/s²

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.