Given: nm ∥ xz prove: △xyz ~ △nym we know that side nm is to side xz. if we consider side ny the transversal for these parallel lines, we create angle pairs. using the , we can state that ∠yxz is congruent to ∠ynm. we know that angle xyz is congruent to angle by the reflexive property. therefore, triangle xyz is similar to triangle nym by the similarity theorem.

Solution:

In  ΔXYZ and ΔNYM

NM ║XZ, YNX is a transversal.

1. ∠YNM= ∠ YXZ→→→[Alternate angles, ∵ NM║XZ, and YNX is a transversal]

2. ∠NYM=∠XYZ [ ∠Y is common between two triangles,that is by reflexive property]

→→ΔXYZ ~ ΔNYM ⇒{Angle-Angle Similarity]

g(x) is the negative form of f(x)? because whenever its the negative form it reflects its self over the x axis. idk if this is right though.

step-by-step explanation:

the answer to the expression is 83