In an effort to control vegetation overgrowth, 139 139 rabbits are released in an isolated area free of predators. after 2 2 years, it is estimated that the rabbit population has increased to 556 556 . assuming exponential population growth, what will the population be after another 6 6 months? round to the nearest rabbit.

197

Step-by-step explanation:

Initial population of rabbit is 139

after 2 years , rabbit population is 556

For exponential growth use y=ab^x

where a is the initial population

x is the time period

b is the growth rate, y is the final population

a= 139 is already given

when x=2, the value of y = 557

plug in all the values  in the formula and find out 'b'  

Divide both sides by 139

take square root on both sides

b=2.00180 and b=-2.00180

growth factor cannot be negative

So b= 2.0018

The equation y=ab^x  becomes

To find population after 6 months

1 year = 12 months

so 6 months = 0.5 years

we plug in 0.5 for x

y= 196.66

so population after 6 months = 197

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3