What is the equation of a line that passes through the point (9,3) and is parallel to the line whose equation is 2x-3y=6 me on this.

The equation of the line would be y = 2/3x - 3

Step-by-step explanation:

In order to find the equation of the line, we first need to find the slope of the original line. We can do that by solving for y.

2x - 3y = 6

-3y = -2x + 6

y = 2/3x - 2

Now that we have a slope of 2/3, we know the new slope will be the same since parallel lines have the same slope. So we can use it along with the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 3 = 2/3(x - 9)

y - 3 = 2/3x - 6

y = 2/3x - 3

a² + b²= c²

24² + 7² = c²

c= 25

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .