The dimensions of a square are altered so that 8 inches is added to one side while 3 inches is subtracted from the other. the area of the resulting rectangle is 126 in^2. what was the original side length of the square

Let

x> original length side of a square

we know that

area rectangle=length*width

area=126 in²

length=(x+8)

width=(x-3)

so

126=(x+8)*(x-3)> x²-3x+8x-24=126> x²+5x-150=0

using  a graph tool> to resolve the second order equation

see the attached figure

the solution is

x=10 in

the answer is

the original length side of a square is 10 in

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: