Ateacher used the change of base formula to determine whether the equation below is correct. (log2 10)(log4 8)(log10 4)=3

The equation is correct

Step-by-step explanation:

(log2 10)(log4 8)(log10 4)=3

Change of base formula

logb (x) = log10 (x)/ log10 (b)

Lets change all non base 10 logs to base 10 logs

(log2 10) = log10 (10)/ log10 (2)  

We know that log10 (10 ) = 1  so

(log2 10) = 1/ log10 (2)

(log4 8)  = log10 (8)/ log10 (4)

Now we can rewrite the original equation in all base 10

(log2 10)(log4 8)(log10 4)=3

1/ log10 (2) *  log10 (8)/ log10 (4) *  (log10 4)=3

I can cancel the log10 (4)/ log10 (4)

1/ log10 (2) *  log10 (8)=3

log10 (8)/ log10 (2)

We know that 8 = 2^3

log10 (2^3)/ log10 (2) =3

Remember  log a^b  = b * log a

3 * log10 (2) / log10 (2) =3

We can cancel log 10 (2)/ log10 (2)

3=3

The equation is correct

divide by 5

step-by-step explanation:

60/5 = 12

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers