Acooler contains 5 bottles of lemonade 4 bottles of water and 3 bottles of juice each type is equally likely to be chosen based on based on your simulation how many times must a drink be chosen in order to get each type

The number of times a drink must be chosen in order to get each type is:

                                 10

Step-by-step explanation:

It is given that:

a cooler contains 5 bottles of lemonade 4 bottles of water and 3 bottles of juice.

Now we have to choose the maximum number of bottles such that we have got a drink of each type.

Let us suppose at the first 9 draws we did not get any bottle of juice and only got all the bottles of lemonade and water.

Since we know that the sum of 5+4=9

after which at the tenth draw we will definitely get a bottle of juice since all the other drinks were chosen in the previous draw.

idk

step-by-step explanation:

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