Write an equation in slope intercept form of a line that passes through the point (14, 8) and is (a) parallel (v) perpendicular to the line that passes through the points (4,9) and (-3, 6)

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point and a slope from the equation. We will chose point-slope since we have a point and can find the slope.

Point slope:

We must find the slope using the slope formula.

Slope:

We substitute and

in our new equation because it is perpendicular to it. This means we will need to change it into its negative reciprocal which is .

We will substitute and .

This is the equation of the line perpendicular to the equation line through the points given that crosses through (14,8).

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.