Tom has a can of paint that covers 37 and a 1/2 m² each board on the fence has an area of 3/16th square meters how many boards can he paint

200

Step-by-step explanation:

3/16= .1875

Take the amount of paint you have, 37.5, and divide it by the amount of space, .1875

37.5/.1875= 200

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)