Need with asap . which ordered pair is a solution to the linear functions 2x-y 1/3y=x (0,2) (1,3) (2,6) (3,8)

(1,3) & (2,6) are solutions to 1/3y=x. No solution is listed for 2x=y.

Step-by-step explanation:

To find find if an ordered pair is a solution, we can graph the line and look for the point on the line or evaluate the equation with the solution as the variable values.

We will substitute (x,y) for a given solution and find if the equation holds true.

For 2x=y

(0,2)                (1,3)                   (2,6)                  (3,8)

2(0)=2             2(1)=3                2(2)=6              2(3)=8

0=2 FALSE     2=3 FALSE        4=6   FALSE    6=8 FALSE

For 1/3y=x.

(0,2)                   (1,3)                      (2,6)                     (3,8)

1/3(2)=0             1/3(3)=1               1/3(6)=2              1/3(8)=3

2/3=0 FALSE     1=1 TRUE           2=2   TRUE          8/3=3 FALSE

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°