In which quadrant will the triangle be located after this series of transformations? does the size of the triangle change after the series of transformations? 1. translate (x, y) → (x + 1, y + 2) 2. r (origin, 90° clockwise) 3. translate (x, y) → (x + 2, y - 3) a) quadrant ii; no b) quadrant iv; no c) quadrant iii; no d) quadrant ii; yes

Step-by-step explanation:

Vertices are (1,1) (3,1) (2,5)

1) Translation gives vertices as

(2,3) (4,3) (3,7)

2) Reflection origin 90 degrees clockwise

(-3,2) (-3,,4) (-7,3)

3) translation is

(-1,-1)(-2,1) (-5,0)

So lies in quadrant 3.

Hey, the answer is B. Quadrant IV;no

Step-by-step explanation:

I added a picture, the blue triangle is after the first translation, the black triangle is after step two, the rotation, and the red triangle is what we end up with after the final translation. Is you can see, it ended up in Quadrant IV (i marked the quadrants for you), and the size didn't change because it was simply rigid transformations. I hope I helped!

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm